18r^2-18r-2=-2

Solution for 18r^2-18r-2=-2 equation:

18r^2-18r-2=-2

We move all terms to the left:

18r^2-18r-2-(-2)=0

We add all the numbers together, and all the variables

18r^2-18r=0

a = 18; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·18·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*18}=\frac{0}{36}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*18}=\frac{36}{36}
=1
$